Question

What is the deBroglie wavelength of an electron moving at 1.37 x 106 m/s if the mass of the electron is 9.11 x 10-28 g

Answer 1

The value is
`\lambda = 5.30 *10^(-10 ) \ m`

Step-by-step explanation:

From the question we are told that

The velocity of the electron is
`v = 1.37 *10^(6) \ m/s`

The mass of the electron is
`m = 9.11 *10^(-28) \ g = 9.11 *10^(-31) \ kg`

Generally the deBroglie wavelength is mathematically represented as

`\lambda = (h)/(mv)`

Here h is the Planck'c constant with value
`h = 6.62607015 * 10^(-34) J \cdot s`

So

`\lambda = (6.62607015 * 10^(-34) )/(9.11 *10^(-31) * 1.37 *10^(6))`

=>
`\lambda = 5.30 *10^(-10 ) \ m`