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Find the complex power, average power, and reactive power for the following:

v(t) = 339.4 sin (377t + 90°) V, i(t) = 5.657 sin (377t + 60°) A

User Ezhil
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1 Answer

6 votes

Answer:

Step-by-step explanation:

Given that:

v(t) = 339.4 sin(377t + 90°) V

i(t) = 5.657 sin (377t + 60°) A

v = 339.4 ∠ 90°
v_m \angle\phi_1

i = 5.657∠60°
I_m \angle \phi_2

The phase difference
\phi = 90 -60 = 30

The average power
P_(avg) can be expressed as:


P_(avg) = (v_m)/(√(2))(I_m)/(√(2)) * cos (30)


P_(avg) = (339.4)/(√(2))*(5.657)/(√(2)) * cos (30)


\mathbf{P_(avg) = 831.38 \ watts}

The reactive power Q is as follow;


Q = (v_m)/(√(2)) * (I_m)/(√(2)) \ sin \phi\\


Q = (339.4)/(√(2))*(5.657)/(√(2)) * sin (30)

Q = 479.99 VAR

The complex power S = P + jQ

The complex power S = 831.38 W + j479.99 VAR

User Heyji
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