Answer:
Step-by-step explanation:
Given that:
v(t) = 339.4 sin(377t + 90°) V
i(t) = 5.657 sin (377t + 60°) A
v = 339.4 ∠ 90°
![v_m \angle\phi_1](https://img.qammunity.org/2021/formulas/engineering/college/qqw17bwcihla28h5z900zun3pfw3hx23r8.png)
i = 5.657∠60°
![I_m \angle \phi_2](https://img.qammunity.org/2021/formulas/engineering/college/sda74ihjeyauovml9wcxobs4q9tr0l3ukb.png)
The phase difference
= 30
The average power
can be expressed as:
![P_(avg) = (v_m)/(√(2))(I_m)/(√(2)) * cos (30)](https://img.qammunity.org/2021/formulas/engineering/college/ges747i6qqvy2czjoyy3ak3us5rs2puu3t.png)
![P_(avg) = (339.4)/(√(2))*(5.657)/(√(2)) * cos (30)](https://img.qammunity.org/2021/formulas/engineering/college/t9eexqdkfyf733o49ed8d9w1s0gdljv3wa.png)
![\mathbf{P_(avg) = 831.38 \ watts}](https://img.qammunity.org/2021/formulas/engineering/college/o83tsxrt98fkuntgzpat0km2ehnchua9un.png)
The reactive power Q is as follow;
![Q = (v_m)/(√(2)) * (I_m)/(√(2)) \ sin \phi\\](https://img.qammunity.org/2021/formulas/engineering/college/3lzi1mycs1z66mivh9t20gpiyegzzcgpml.png)
![Q = (339.4)/(√(2))*(5.657)/(√(2)) * sin (30)](https://img.qammunity.org/2021/formulas/engineering/college/dlik8yw7q80p4b2bv0xy09dl3fnhk7rko5.png)
Q = 479.99 VAR
The complex power S = P + jQ
The complex power S = 831.38 W + j479.99 VAR