Question

A spherical Gaussian surface of radius R is situated in space along with both conducting and insulating charged objects. The net electric flux through the Gaussian surface is:______

Answer 1

Ф =
`(Q)/(e_(0) ) [ ((4\pi )/(3 )(R)^3 )/((4)/(3)\pi (R)^3 ) ]`

Step-by-step explanation:

Radius of Gaussian surface = R

Charge in the Sphere ( Gaussian surface ) = Q

lets take the radius of the sphere to be equal to radius of the Gaussian surface i.e. R

To determine the net electric flux through the Gaussian surface

we have to apply Gauci law

Ф = 4
`\pi r^2 E`

Ф =
`(Q_(enc) |)/(e_(0) )`

=
`(Q)/(e_(0) ) [ ((4\pi )/(3 )(R)^3 )/((4)/(3)\pi (R)^3 ) ]`