Answer:
Answer: -1
Explanation:
The Polynomial Remainder Theorem
It states that the remainder of the division of a polynomial f(x) by (x-r) is equal to f(r).
We have the polynomial:
![f(x)=x^3+x^2+x+1](https://img.qammunity.org/2021/formulas/mathematics/high-school/4uk92snnmwu9moj2xvhb5t4t9fuq431ii6.png)
And we need to determine if x=1 and/or x=-1 are zeros of the polynomial.
Considering the polynomial remainder theorem, if we try any value for x, and the remainder is zero, then that value of x is a root or zero of the polynomial.
Find:
![f(1)=1^3+1^2+1+1](https://img.qammunity.org/2021/formulas/mathematics/high-school/d3yaj6fzk0ucw67v7h4x0wlra2a8256wuu.png)
f(1)=4
Thus, x=1 is not a zero of f(x)
Now, find:
![f(-1)=(-1)^3+(-1)^2+(-1)+1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ua753gls6liwigw1am6vxxstab4l6msj3d.png)
![f(1)=-1+1-1+1=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/ja2s09pyq1pabyizhu2968gazufm6vfkhn.png)
Thus, x=-1 is a zero of f(x)
Answer: -1