Question

Can someone help me with my math

Answer 1

It is the first one. 5y^3/x^2z^12

Explanation:

First, divide each component by its self

1. 20/4=5

2. x/x^3 1/x^3 You divide exponents by subtracting them.

3. y^4/y = Y^3

4. z^12/z^24= 1/z^24

5. Then put all of it into the same equation. 5y^3/x^2z^12

Answer 2

Answer: Choice A)
`(5y^3)/(x^2z^(12))`

This is the fraction
`5y^3` over
`x^2z^(12)`

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Work Shown:

`(20xy^4z^(12))/(4x^3yz^(24))\\\\(20)/(4)*(x)/(x^3)*(y^4)/(y)*(z^(12))/(z^(24))\\\\5x^(1-3)y^(4-1)z^(12-24)\\\\5x^(-2)y^(3)z^(-12)\\\\5*(1)/(x^2)*y^(3)*(1)/(z^(12))\\\\(5y^3)/(x^2z^(12))`