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Estimate the turning point of the graph y=x^3+x^2-6x

User Mssb
by
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1 Answer

3 votes

Answer:

X=0,X= -3,X=2

Explanation:

y=x^3+x^2-6x

0=x^3+x^2-6x

x^3+x^2-6x=0

x ×(x^2+x-6)=0

x ×(x^2+3x-2x-6)=0

x ×(xx(x+3)-2(X+3))=0

x ×(x+3)x(x-2)=0

x=0

x+3=0

x-2=0

x=0

x= -3

x=2

sana nakatulong

User Romulo Freires
by
8.5k points

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