Question

What volume of a 0.155 M potassium hydroxide solution is required to neutralize 25.7 mL of a 0.388 M hydrobromic acid solution

Answer 1

Answer: Therefore, the volume of a 0.155 M potassium hydroxide solution is 56.0 ml

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

`n_1M_1V_1=n_2M_2V_2`

where,

`M_1` = molarity of
`HBr` solution = 0.338 M

`V_1` = volume of
`HBr` solution = 25.7 ml

`M_2` = molarity of
`KOH` solution = 0.155 M

`V_2` = volume of
`KOH` solution = ?

`n_1` = valency of
`HBr` = 1

`n_2` = valency of
`KOH` = 1

`1* 0.338* 25.7=1* 0.155* V_2`

`V_2=56.0ml`

Therefore, the volume of a 0.155 M potassium hydroxide solution is 56.0 ml