Question

What is an equation in slope-intercept form for the line that passes through the points (1,-3) and (3,1)

Answer 1

Explanation:

Hey there!

Note: Use double point formula for finding the eqaution which passes through two points.

Given;

The points are; (1,-3) and (3,1).

Use double point formula.

`(y - y1) = (y2 - y1)/(x2 - x2) (y - y1)`

Put all values.

`(y + 3) = (1 + 3)/(3 - 1) (x - 1)`

Simplify it.

`(y + 3) = (4)/(2) (x - 1)`

`y + 3 = 2(x - 1)`

`y + 3 = 2x - 2`

`y = 2x - 2 - 3`

`y = 2x - 5`

Therefore, the eqaution is y = 2x-5.

Alternative:

Steps:

• Find slope using slope formula and use one point formula.
• Simplify in the form of y = mx+c form.

Formula:

• Slope = (y2-y1)/(x2-x1)
• One point formula= (y-y1)= m(x-x1)

The points are; (1,-3) and (3,1).

Now;

Slope= (1- (-3))/(3-1)

= (1+3)/2

= 2

Again;

Using one-point formula.

(y+3) = 2(x-1)

y+3= 2x-2

y = 2x -5

Therefore, the equation is y = 2x-5.

(You can follow up any method you want)

Hope it helps....