Question

2x^-3 y^-2
——————
4xy^5

Answer 1

`~~(2x^(-3) y^(-2))/(4xy^5)\\\\\\=\frac 12\cdot x^(-3-1) \cdot y^(-2-5)~~~~~~~~~~~~~~~~~~~~~~;\left[(a^m)/(a^n) = a^(m-n)\right]\\\\\\=\frac 12\cdot x^(-4) \cdot y^(-7)\\\\\\=(1)/(2x^4 y^7)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~;\left[k^(-n) = \frac 1{k^n},~ k\\eq 0\right]`