Question

Solubility

Mixtures and Solutions
Acellus
If 1.23 g of chlorine gas dissolves in
0.95 L of water at 15.6 psi, at what
pressure (in psi) would you be able
to dissolve 1.89 g in the same
amount of water?

Answer 1

Answer:24.0

Step-by-step explanation:

Answer 2

The pressure : 23.48 psi

Further eplanation

Henry's Law stated that the solubility of a gas is proportional to its partial pressure

Can be formulated

S = kH. P.

S = gas solubility, mol / L

kH = Henry constant, mol / L.atm

P = partial gas pressure

• 1.23 g Cl₂

MW Cl₂ = 71 g/mol

mol of 1.23 g Cl₂ :

`\tt mol=(1.23)/(71)=0.017`

Solubility O₂ : 0.017 mol/0.95 L =0.01789 mol/L

Henry's constant for O₂ :

P = 15.6 psi= 1.061517 atm

`\tt S=kH.P\\\\kH=(0.01789)/(1,061517)=0.0169`

• 1.89 g Cl₂

`\tt (1.89)/(71)=0.026`

`\tt S=0.026:0.95=0.027\\\\P=(S)/(kH)=(0.027)/(0.0169)=1.598~atm=23,48~psi`