Question

Carol has some dimes and quarters. If she has 19 coins worth a total of $3.10, how many of each type of coin does she have?

Answer 1

She has 8 quarters 11 dimes

Answer 2

Explanation:

Equations

Let the dimes be x

Let the quarters be y

x + y = 19 (1) Multiply this equation by 0.1

0.1x + 0.25y = 3.10 (2)

0.1x + 0.1 y = 1.90 (3) Subtract 3 from 2

0.15y = 1.20 Divide by 0.15

0.15y/0.15 = 1.20/0.15

y = 8

x + y = 19

x + 8 = 19 Subtract 8 from both sides

x+8-8 = 19-8 Combine

x = 11

Answer

Carol has 8 quarters

She has 11 dimes