Solution:
Work:
- [1/2(n)(n + 1)] + [1/2(n + 1)(n + 2)]
Simplifying in Brackets
- => [1/2(n² + n)] + [1/2(n² + 2n + n + 2)]
- => [n²/2 + n/2] + [n²/2 + n + n/2 + 1]
Removing Brackets.
- => n²/2 + n/2 + n²/2 + n + n/2 + 1
Solving.
Since the result has a "square" sign, the statement is proved has true.
Hoped this helped.