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What is the simplest form of 3^ √27t^9/729?

t^3/27

t^6/27

t^3/3

t^6/3

What is the simplest form of 3^ √27t^9/729? t^3/27 t^6/27 t^3/3 t^6/3-example-1
User Cogicero
by
7.3k points

2 Answers

7 votes

Answer:

the third option is correct

Explanation:

:)

User Porkbutts
by
7.9k points
2 votes

Answer:


(t^(3) )/(3)

Explanation:


\sqrt[3]{(27t^(9) )/(729) } 27 is a perfect cube for
3^(3) and 729 is a perfect cube for
9^(3)


\sqrt[3]{(3^(3) t^(9) )/(9^(3) ) } now you can pull out the numbers from under the root, for t (divide the exponent by 3)


(3)/(9)
t^(3) now simply to
(t^(3) )/(3)

User Baraa
by
8.8k points

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