Question

What is the simplest form of 3^ √27t^9/729?

t^3/27

t^6/27

t^3/3

t^6/3

Answer 1

the third option is correct

Explanation:

:)

Answer 2

`(t^(3) )/(3)`

Explanation:

`\sqrt[3]{(27t^(9) )/(729) }` 27 is a perfect cube for
`3^(3)` and 729 is a perfect cube for
`9^(3)`

`\sqrt[3]{(3^(3) t^(9) )/(9^(3) ) }` now you can pull out the numbers from under the root, for t (divide the exponent by 3)

`(3)/(9)`
`t^(3)` now simply to
`(t^(3) )/(3)`