Question

2. A generator coil has 25 turns of wire and a cross-sectional area of 36 cm2.

The maximum emf developed in the generator is 2.8 V at 60 Hz. What is
the strength of the magnetic field in which the coil rotates?

Answer 1

Angular speed

• 2πf

f is frequency

• 2(3.14)(60)
• 376.8

Area=36cm²=0.0036m²

Now

`\\ \rm\Rrightarrow emf=nAB\omega`

`\\ \rm\Rrightarrow 2.8=25* 36* 10^(-4)* 376.8B`

`\\ \rm\Rrightarrow 2.8=33.84B`

`\\ \rm\Rrightarrow B=0.0827T`

`\\ \rm\Rrightarrow 8.3* 10^(-3)T`