132k views
18 votes
Write 3 + 2 log z - log(x² + 2x + 1) +1/2 log y as a single logarithm with coefficient 1.​

User IamAshay
by
8.5k points

1 Answer

12 votes

Answer:


\displaystyle \log\frac{1000z^2y^{(1)/(2)}}{(x+1)^2} OR
\displaystyle 3+\log\frac{z^2y^{(1)/(2)}}{(x+1)^2}

Choose the more appropriate answer

Explanation:

I read your problem as
3+2\log z-\log(x^2+2x+1)+(1)/(2)\log y:


\displaystyle 3+2\log z-\log(x^2+2x+1)+(1)/(2)\log y\\\\\log1000+\log z^2-\log(x+1)^2+\log y^{(1)/(2)}\\\\\log1000z^2-\log(x+1)^2+\log y^{(1)/(2)}\\\\\log(1000z^2)/((x+1)^2)+\log y^{(1)/(2)}\\\\\log\frac{1000z^2y^{(1)/(2)}}{(x+1)^2}

User Misbah
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories