Which shows the un-simplified solution for x2 + 8x + 6 = 0?

Question

asked Oct 25, 2023 50.4k views

2 Answers

Nafeesa · Answer 1 · 2023-10-28T01:05:45+0000

Answer:

Choice A

Explanation:

Let's solve to check.

Given:

x^2 + 8x + 6 = 0

Solution:

We know that,

$\implies \rm \: x = \cfrac{ { - b±} \sqrt{ {b}^(2) - 4(ac)} }{2a}$

So substitute them:

$\implies \rm \: x = \cfrac{ - 8± \sqrt{ {8}^(2) - 4(1 * 6)} }{2 * 1}$

$\implies \rm \: x = \cfrac{ - 8± √(64 - 4 * 6 ) }{2}$

$\implies \rm \: x= \cfrac{ - 8 ±√(64 - 24) }{2}$

$\boxed{ \implies \rm \: x = \cfrac{ - 8 ±√(40)}{2}}$

Hence, choice A[x = {8±√(40)/2}] shows the un-simplified solution for x2 + 8x + 6 = 0.

Jom George · Answer 2 · 2023-10-31T02:43:29+0000

Answer:

A)
$\displaystyle x=(-8\pm√(40))/(2)$

Explanation:

We know that the discriminant is
b^2-4ac=(8)^2-4(1)(6)=64-24=40 , so it cannot be B or C.

Also, because
2a=2(1)=2 , then the denominator must be 2, which means that A is the correct un-simplified solution for the quadratic equation.