Question

Please answer!!

Use the parabola tool to graph the quadratic function.

f(x)=3x^2+6x−24

Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

Answer 1

See below

Explanation:

`f(x)=3x^2+6x-24\\\\f(x)=3(x^2+2x-8)\\\\f(x)+3(9)=3(x^2+2x-8+9)\\\\f(x)+27=3(x^2+2x+1)\\\\f(x)=3(x+1)^2-27`

Here, we can see that the vertex of the parabola is
`(-1,-27)` when we compare to the equation
`y=(x-h)^2+k` with vertex
`(h,k)`.

A second point you could plot is the y-intercept, when
`x=0`:

`f(0)=3(0+1)^2-27\\\\f(0)=3-27\\\\f(0)=-24`

So, your y-intercept is
`(0,-24)`.