29.6k views
1 vote
When a 12 N horizontal force is applied to a box on a horizontal tabletop, the box remains at rest. The force of friction acting on the box is

1) 0N
2) Between 0N and 12N
3) Exactly 12 N
4) Greater than 12N​

User Heady
by
4.6k points

2 Answers

2 votes

Final answer:

The force of friction acting on the box when a 12 N horizontal force is applied and the box remains at rest is exactly 12 N, which balances the applied force to maintain a net force of zero.

Step-by-step explanation:

When a 12 N horizontal force is applied to a box on a horizontal tabletop, and the box remains at rest, the force of friction acting on the box is exactly 12 N. This is because according to Newton's first law of motion, an object will remain at rest if the net external force acting on it is zero. In this case, since the force applied is 12 N to move the box and it does not move, the frictional force must be 12 N in the opposite direction to counteract this force, resulting in a net force of zero.

User Stsquad
by
4.9k points
5 votes

Answer:

12N

Step-by-step explanation:

when a force is applied to a body but still stays at rest or moves at a constant speed , the frictional force is equal to the force applied

User Ankur Chauhan
by
4.6k points