Answer:
10.8 g
Step-by-step explanation:
A chemist adds 480.0 mL of a 0.169 mol/L aluminum chloride solution to a reaction flask. Calculate the mass in grams of aluminum chloride the chemist has added to the flask. Round your answer to 3 significant digits.
Step 1: Given data
- Volume of the solution: 480.0 mL
- Concentration of the aluminum chloride solution: 0.169 mol/L
Step 2: Calculate the moles of aluminum chloride in the solution
We will multiply the volume of the solution by the molarity.
0.4800 L × 0.169 mol/L = 0.0811 mol
Step 3: Calculate the mass corresponding to 0.0811 moles of AlCl₃
The molar mass of AlCl₃ is 133.34 g/mol.
0.0811 mol × 133.34 g/mol = 10.8 g