Question

Uche pumps gasoline at a rate of 18\,\dfrac{\text{L}}{\text{min}}18 min L ​ 18, start fraction, start text, L, end text, divided by, start text, m, i, n, end text, end fraction. What is Uche's pumping rate in \dfrac{\text{mL}}{\text{s}} s mL ​ start fraction, start text, m, L, end text, divided by, start text, s, end text, end fraction? \dfrac{\text{mL}}{\text{s}} s mL ​

Answer 1

Question:

Uche pumps gasoline at a rate of 18 L/min. What is Uche's pumping rate in mL/s?

Answer:

`Rate = 300mL/s}`

Explanation:

Given

`Rate = (18L)/(min)`

Required

Express as mL/s

First, we need to convert L to mL

`1L = 1000mL`

So:

`Rate = (18 * 1000mL)/(min)`

`Rate = (18000mL)/(min)`

Next, convert min to seconds

`1\ min = 60\ s`

So:

`Rate = (18000mL)/(min)`

`Rate = (18000mL)/(60s)`

`Rate = 300mL/s}`