Question

How much water is produced when 89m of H2 is reacted with 64gm of O2?​

Answer 1

Mass of water produced = 801 g

Step-by-step explanation:

Given data:

Mass of water produced = ?

Mass of H₂ = 89 g

Mass of oxygen = 64 g

Solution:

Chemical equation:

2H₂ + O₂ → 2H₂O

Number of moles of hydrogen:

Number of moles = mass/molar moles

Number of moles = 89 g/ 2 g/mol

Number of moles = 44.5 mol

Number of moles of oxygen:

Number of moles = mass/molar moles

Number of moles = 64 g/ 2 g/mol

Number of moles = 32 mol

Now we will compare the moles of water with oxygen and hydrogen.

H₂ : H₂O

2 : 2

44.5 : 44.5

O₂ : H₂O

1 : 2

32 : 2/1×32 =64 mol

Number of moles of water produced by hydrogen are less thus it yield is limit by hydrogen.

Mass of water:

Mass = number of moles × molar mass

Mass = 44.5 mol × 18 g/mol

Mass = 801 g