The vertex of the graph of y = (x - 1)2 - 5 is

Question

asked Dec 26, 2021 64.1k views

2 Answers

Amandeep Rohila · Answer 1 · 2021-12-27T15:24:19+0000

Answer:

1,-5

Explanation:

for y = (x-h)^2 + k

the vertex is h,k

comparing

y=(x-1)^2-5 with y = (x-h)^2 + k

we have h = 1, k = -5

so the vertex of y=(x-1)^2-5 is (1,-5)