Answer:
1,-5
Explanation:
for y = (x-h)^2 + k
the vertex is h,k
comparing
y=(x-1)^2-5 with y = (x-h)^2 + k
we have h = 1, k = -5
so the vertex of y=(x-1)^2-5 is (1,-5)
(1, -5)
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