Question

Sin^4 x+2sin^2 x-3=0
Solve by factoring on [0,2pi]

Answer 1

Step-by-step explanation:x=π2,3π2

Step-by-step explanation:

This can be factored as (x2+a)x2+b).⇒(sin2x+3)(sin2x-1)=0⇒

2

x

=

−

3

and

sin

2

x

=

1

⇒

sin

x

=

√

−

3

and

sin

x

=

√

1

⇒

sin

x

=

∅

and

sin

x

=

±

1

⇒

x

=

π

2

,

3

π

2

Hopefully this helps!