The input work done on a machine is 9.63 × 103 joules, and the output work is 3.0 × 103 joules. What is the percentage efficiency of the machine?

asked Jul 19, 2021 110k views

1 vote

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7 votes

Answer:

31.15%

Step-by-step explanation:

The formula used was

((Work output)/(Work input))×100

Varit J Patel answered Jul 21, 2021

5.9k points

4 votes

Answer:

C. 31.1 percent

Phani Rithvij answered Jul 24, 2021

6.4k points

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