Question

Feather is dropped from 13 m high after it has fallen 3 m what is its acceleration

Answer 1

Step-by-step explanation:

The constant acceleration of any object, neglecting air resistance and friction, is always -9.8. Proof:

`s(t)=-4.9t^2+13` which is the position of this feather before it is dropped. The first derivative of position is velocity, so the velocity function for the feather is:

`v(t)=-9.8t`. We could find the velocity that the feather is experiencing at 3 seconds, but that is not what we are being asked. What we are being asked is the acceleration of the feather at 3 seconds. So we find the acceleration function of the feather:

a(t) = -9.8

It turns out that the time doesn't matter to acceleration due to gravity because feathers and elephants all fall under the same pull.