Question

Robert uses a wheelbarrow to haul wood from his backyard to the back of the neighbor's house, located 80 m away. If he takes 3 breaks evenly when pushing the wheelbarrow the complete distance, at what distance does he take his first break.

Answer 1

26.66 meters

Explanation:

The final destination of his neighbor's house is 80 meters away so we can assume that the starting point of Robert's backyard is point 0 meters. Since he takes 3 breaks evenly dispersed between the entire trip, then we simply divide the total distance by 3 in order to distance between each break.

80 / 3 = 26.66 m

Therefore, the distance between each breakpoint is 26.66 meters which also means that the first break is taken at a distance of 26.66 meters. This is because since it is the first break it is added to the starting point of 0 like so...

0 + 26.66 = 26.66 meters