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CAN SOMEONE PLEASE HELP ME WITH THIS GEOMETRY QUESTION THANK YOU !!!

CAN SOMEONE PLEASE HELP ME WITH THIS GEOMETRY QUESTION THANK YOU !!!-example-1
User Sfotiadis
by
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1 Answer

3 votes

Answer:


y=20√(1)

Explanation:

The construction of the figure gives us three right triangles, where we can apply Pythagora's Theorem.

I have added two variables to the image in the picture attached.

On the triangle with sides y,h,16 we have:


y^2-16^2=h^2

On the triangle with sides h,z,25 we have:


z^2-25^2=h^2

Equating
h^2:


y^2-16^2=z^2-25^2\qquad\qquad [1]

On the bigger triangle with sides y,z,16+25=41 we have:


y^2+z^2=41^2

Adding this last equation with [1]:


y^2-16^2+y^2+z^2=z^2-25^2+41^2

Simplifying:


2y^2-16^2=41^2-25^2

Operating:


2y^2-256=1681-625


2y^2=1056-256


2y^2=800

Dividing by 2:


y^2=400

Taking square root:

y=20

To enter the number in the required format:


\boxed{y=20√(1)}

CAN SOMEONE PLEASE HELP ME WITH THIS GEOMETRY QUESTION THANK YOU !!!-example-1
User Questzen
by
4.4k points