Final answer:
To find the height of the kite, first calculate the height component by using the sine of the angle of elevation with the string length and then add Jaxon's hand height. The kite is approximately 46.0 feet above the ground.
Step-by-step explanation:
The question involves using trigonometric principles to find the height of a kite above the ground. Given that Jaxon is holding the kite string at a height of 3.25 feet above the ground and the string is 105 feet long with an angle of elevation of 24°, we can use the sine trigonometric ratio to solve for the height of the kite.
To find the height of the kite above the ground, we perform the following calculation:
- Calculate the height from Jaxon's hands to the kite using the sine of the angle of elevation: height = 105 feet × sin(24°).
- Add Jaxon's hand height above the ground to the height calculated in the previous step.
By performing the calculation:
height = 105 feet × sin(24°) = 105 × 0.4067 ≈ 42.7 feet
Now we add Jaxon's hand height to the height of the kite:
Total height above ground = 42.7 feet + 3.25 feet ≈ 45.95 feet
Rounded to the nearest tenth of a foot, the kite is approximately 46.0 feet above the ground.