Question

Factor the perfect-square trinomial in y = (x2 + 2x + 1) − 1− 1.
y = (x +
)2 − 1 −1

Answer 1

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`y = ( {x}^(2) + 2x + 1) - 1`

`y = ({x + 1})^(2) - 1`

`y = ({x + 1})^(2) - ({1})^(2)`

We're done now but I have something to tell...

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Hint :

`{a}^(2) - {b}^(2) = (a + b)(a - b)`

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`y = ( \: (x + 1) + 1)( \: (x + 1) - 1) \\`

`y = (x + 2)(x)`

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Answer 2

1

Explanation: