2 Answers

Sokol · Answer 1 · 2021-02-19T22:36:46+0000

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$y = ( {x}^(2) + 2x + 1) - 1$

$y = ({x + 1})^(2) - 1$

$y = ({x + 1})^(2) - ({1})^(2)$

We're done now but I have something to tell...

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Hint :

${a}^(2) - {b}^(2) = (a + b)(a - b)$

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$y = ( \: (x + 1) + 1)( \: (x + 1) - 1) \\$

y = (x + 2)(x)

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