Answer:
Explanation:
3(x-2)(x-2)-8=5
3[x^2-4x+4]-8-5=0
3x^2-12x+12-13=0
3x^2-12x-1=0
use the quadratic formula to find x { -b+-sqrt(b^2-4ac) } / 2a
where a =3 , b=-12 and c =-1 from our equation above
{ -(-12)+- sqrt[ (-12)^2 - 4(3)(-1) ] } / [2(3)]
{ 12 +- sqrt [ 144 + 12 ] } / 6
{ 12 +- sqrt (156) } / 6
2 +- {sqrt ( 4 *13) } / 6
2 +- { 2 sqrt (13) } /6
2 +- sqrt (13) /3
there you go :)