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I need to drop 10 V to feed an LED from a 12 V power supply. The resistor value is 490 Ω. How much of my battery power will be wasted in the resistor?

User Vijrox
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1 Answer

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Answer:

P = 0.204 W

Step-by-step explanation:

Given that,

Voltage drop is 10 V to feed an LED from a 12 V power supply. The resistor value is 490 Ω.

We need to find how much of my battery power will be wasted in the resistor. The power of a battery is given in terms of voltage and resistance is given by :


P=(V^2)/(R)

V is the voltage drop to feed an LED

Putting all the values,


P=((10)^2)/(490)\\\\P=0.204\ W

So, 0.204 W of power will be wasted in the resistor.

User Sulejman
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5.6k points