Answer:
P = 0.204 W
Step-by-step explanation:
Given that,
Voltage drop is 10 V to feed an LED from a 12 V power supply. The resistor value is 490 Ω.
We need to find how much of my battery power will be wasted in the resistor. The power of a battery is given in terms of voltage and resistance is given by :

V is the voltage drop to feed an LED
Putting all the values,

So, 0.204 W of power will be wasted in the resistor.