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NO LINKS!!! Please help me with this graph. Part 4a​

NO LINKS!!! Please help me with this graph. Part 4a​-example-1
User Dhg
by
8.5k points

2 Answers

4 votes

Answer:


g(x)=(1)/(2)|x-4|+7

Step-by-step explanation:

Translations

For
a > 0


f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}


f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}


y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis by a factor of}\:a

-----------------------------------------------------------------------------------------

Parent function:
f(x)=|x|

(with vertex at the origin)

From inspection of the graph, the vertex of the transformed function is at (4, 7). Therefore, there has been a translation of:

  • 4 units right
  • 7 units up


\implies f(x-4)+7=|x-4|+7

From inspection of the graph, we can see that it has been stretched parallel to the y-axis:


\implies a\:f(x-4)+7=a|x-4|+7

The line goes through point (0, 9)

Substituting this point into the above equation to find
a:


\implies a|0-4|+7=9


\implies 4a=2


\implies a= (1)/(2)

Therefore,


\implies g(x)=(1)/(2)|x-4|+7

User Paquettg
by
8.1k points
3 votes

Answer:


\large{\boxed +7}

Step-by-step explanation:

Absolute value of a graph formula:

  • y = a |x -h| + k

Identify the vertex : (h, k) = (4, 7)

Take two points: (4, 7), (6, 8)


\sf Find \ slope \ (a) : \sf \ (y_2 - y_1)/(x_2- x_1) \ = \ (8-7)/(6-4) \ = (1)/(2)

Putting them together :
\bf g(x) = (1)/(2) |x - 4| +7

User Bernhard Thalmayr
by
8.0k points

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