Question

A bullet of mass 25 g moving with a velocity of 200 cm/s is stopped within 5 cm of the target. The average resistance offered by the target is:​

Answer 1

vf²=vi²-2ad (vf=0, stop)

vi²=2ad

200²=2.a.5

a = 200² : 10

F = ma

F = 25 x 200² : 10

F = 1 x 10⁵ dyne = 1 N

Answer 2

`\huge{\boxed{{\colorbox{red}{1 N}}}}`

that's my answer