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If the volume of a sphere is 256π/3 what is the radius?

User Pheepster
by
3.9k points

2 Answers

10 votes

Answer:

4

Explanation:

The volume of a sphere is equal to 4/3πr³.

Set up the equation;

4/3πr³=256π/3

Multiple both sides by 3/(4π):

r³=64

r=∛64=4 (ans)

User Kelan
by
3.3k points
11 votes

Answer:


\boxed {\boxed {\sf r=4}}

Explanation:

The volume of a sphere is calculated using the following formula:


v= (4)/(3) \pi r^3

The volume of the sphere is
\frac {256 \pi}{3}. Substitute this value in for v.


(256 \pi)/(3) = (4)/(3) \pi r^3

We are solving for the radius, so we must isolate the variable r. It is being multiplied by 4/3π. We can divide by this fraction or multiply by the reciprocal. The reciprocal is the fraction flipped, or 3/4π


\frac {3}{4 \pi} *(256 \pi)/(3) = (4)/(3) \pi r^3 *\frac {3}{4 \pi}


\frac {3}{4 \pi} *(256 \pi)/(3) = r^3


64 =r^3

The variable is being cubed. The inverse of a cube is the cube root, so we take the cube root of both sides of the equation.


\sqrt[3]{64}=\sqrt[3]{r^3}


\sqrt[3]{64}=r


4=r

The radius of the sphere is 4.

User Shantanuo
by
4.2k points