Question

Suppose a disk drive has the following characteristics: Six surfaces 16,383 tracks per surface 63 sectors per track 512 bytes/sector Track-to-track seek time of 8.5ms Rotational speed of 7,200rpm a) What is the capacity of the drive

Answer 1

The answer is "2.95 GB"

Step-by-step explanation:

Given value:

Surfaces = 6

The tracks per surface =16,383

The sectors per track = 63

bytes/sector = 512

Track-to-track seek time = 8.5ms

The Rotational speed = 7,200rpm

`\text{Drive capacity= surface} * \text{tracks per surface} * \text{sectors per track} * (bytes)/(sector)`

`= 6 * 16383 * 63 * 512 \\\\= 3170700288 \ B\\\\ = 3023.81543 \ MB \\\\= 2.95294 \ GB\\`

The drive capacity is 2.95 GB