Answer:
The standard deviation of the number of dogs who weigh 65 lbs or more is 1.83.
Explanation:
Let X represent the number of adult Australian sheep dogs weighing 65 pounds or more.
It is provided that the probability of occurrence of X is, p = 0.40.
A sample of n = 14 adult dogs is studied.
Each dog's weight is independent of the others.
The random variable X follows a Binomial distribution.
The standard deviation of a Binomial distribution is:
![\sigma=√(np(1-p))](https://img.qammunity.org/2021/formulas/mathematics/high-school/1ppleqa5coc945q9lsj52xzb1c4ho62pek.png)
Compute the standard deviation of the number of dogs who weigh 65 lbs or more as follows:
![\sigma=√(np(1-p))](https://img.qammunity.org/2021/formulas/mathematics/high-school/1ppleqa5coc945q9lsj52xzb1c4ho62pek.png)
![=√(14* 0.40(1-0.40))\\\\=√(3.36)\\\\=1.83303\\\\\approx 1.83](https://img.qammunity.org/2021/formulas/mathematics/college/nb0erzo6rpbk4xi4os8kz3jprt4c04ks8b.png)
Thus, the standard deviation of the number of dogs who weigh 65 lbs or more is 1.83.