Question

A spring stretches by 21.0 cm when a 135 N object is attached. What is the weight of a fish that would stretch the spring by 31 cm?

Answer 1

199.28 N

Step-by-step explanation:

It is given that,

A spring stretches by 21.0 cm when a 135 N object is attached.

We need to find the weight of a fish that would stretch the spring by 31 cm.

We know that, the force in a spring is given by as per Hooke's law as follows :

F = kx

Where k is spring constant

`(F_1)/(F_2)=(x_1)/(x_2)\\\\(135)/(F_2)=(21)/(31)\\\\F_2=(135* 31)/(21)\\\\F_2=199.28\ N`

So, the required weight of a fish is 199.28 N.