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Do this ASAP and put answers in the "Answer" Tab. Any Absurd answers shall be reported and deleted. Remember when your answer gets deleted you loose the points you received.
\boxed{ Perimeter\; and\; Area\; on \;the \;Coordinate \;Plane}

Do this ASAP and put answers in the "Answer" Tab. Any Absurd answers shall-example-1
Do this ASAP and put answers in the "Answer" Tab. Any Absurd answers shall-example-1
Do this ASAP and put answers in the "Answer" Tab. Any Absurd answers shall-example-2
Do this ASAP and put answers in the "Answer" Tab. Any Absurd answers shall-example-3
User Jgr
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.....................part \: 1. \: a.......................... \\\boxed{ Perimeter} \\ the \: perimeter \: of \: a \: triangle \: is \: given \: by \to\\ \boxed{p} = a + b + c........ \\ were \: \\ a \: b \: and \: c \: are \: the \: sides \: \: of \:the \: triangle \: when : \\ a = su = \: ?\\ b = ut = 8 \: units\\ c = ts = 14 \: units\\ to \: find \: su \: we \: apply \: pythagorean \: rule\: \to \: \\ (su) {}^(2) = {(ut)}^(2) + {(ts)}^(2) \\ su = \sqrt{ {8}^(2) + {14}^(2) } \\ su = 2 √(65) \\ hence : \\ \boxed{p} = 8 + 14 + 2 √(65) \\ p = 22 + 2 √(65) \\\boxed{p= 38 .12\: units}\\ \\ .......................part \: 1. \: b....................... \\ \boxed{Area} \\ the \: area \: of \: a \: triangle \: is \: given \: by : \\ A = (1)/(2) bc \\ hence : \\ A = (1)/(2) * 8 * 14 \\ \boxed{ A = 56\: {units}^(2)}

Note.......I took care of part 1 only......cos handling both questions on here will be much on me

or.......you can set part 2 as a different question......but applying the same methods for the triangle will definitly work for the rectangle.

♨Rage♨

User Titusz
by
7.9k points
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