Question

Do this ASAP and put answers in the "Answer" Tab. Any Absurd answers shall be reported and deleted. Remember when your answer gets deleted you loose the points you received.
`\boxed{ Perimeter\; and\; Area\; on \;the \;Coordinate \;Plane}`

Answer 1

`.....................part \: 1. \: a.......................... \\\boxed{ Perimeter} \\ the \: perimeter \: of \: a \: triangle \: is \: given \: by \to\\ \boxed{p} = a + b + c........ \\ were \: \\ a \: b \: and \: c \: are \: the \: sides \: \: of \:the \: triangle \: when : \\ a = su = \: ?\\ b = ut = 8 \: units\\ c = ts = 14 \: units\\ to \: find \: su \: we \: apply \: pythagorean \: rule\: \to \: \\ (su) {}^(2) = {(ut)}^(2) + {(ts)}^(2) \\ su = \sqrt{ {8}^(2) + {14}^(2) } \\ su = 2 √(65) \\ hence : \\ \boxed{p} = 8 + 14 + 2 √(65) \\ p = 22 + 2 √(65) \\\boxed{p= 38 .12\: units}\\ \\ .......................part \: 1. \: b....................... \\ \boxed{Area} \\ the \: area \: of \: a \: triangle \: is \: given \: by : \\ A = (1)/(2) bc \\ hence : \\ A = (1)/(2) * 8 * 14 \\ \boxed{ A = 56\: {units}^(2)}`

Note.......I took care of part 1 only......cos handling both questions on here will be much on me

or.......you can set part 2 as a different question......but applying the same methods for the triangle will definitly work for the rectangle.

♨Rage♨