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Write the equation of the circle whose center is (-5, -8) with diameter 12

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Answer:

(x + 5)^2 + (y + 8)^2 = 6^2

Explanation:

A circle formula: (x - h)^2 + (y - k)^2 = r^2

We are given diameter. To find the radius divide diameter by 2.

d = 12

12/2 = r = 6

H and K are given to be (-5 , -8)

(x - (-5))^2 + (y - (-8))^2 = 6^2

(x + 5)^2 + (y + 8)^2 = 6^2

I have plot this equation to confirm my answer is correct where the origin is (-5 , -8) and has a radius of 6.

Write the equation of the circle whose center is (-5, -8) with diameter 12-example-1
User RegarBoy
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