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(A-5)² + (B- 3)² = 18 B=A-2 A = ?, B = ?​

User Kyle Ivey
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1 Answer

12 votes

Answer:

A = 8 and B = 6

Explanation:

Since (B = A - 2), we can substitute (A - 2) in for the "B" variable in the first equation to isolate "A".

(A - 5)² + (B - 3)² = 18 -----> Original equation

(A - 5)² + ((A - 2) - 3)² = 18 -----> Plug in B = A - 2

(A - 5)² + (A - 5)² = 18 -----> Subtract

(A² - 10A + 25) + (A² - 10A + 25) = 18 -----> Expand parentheses

2A² - 20A + 50 = 18 ------> Add like terms

2A² - 20A + 32 = 0 -----> Subtract 18 from both sides

2(A² - 10A + 16) = 0 -----> Remove common factor

2(A - 2)(A - 8) = 0 -----> Factor within parentheses

A = 2 -----> Find A - 2 = 0

A = 8 -----> Find A - 8 = 0

Since "A" gave two possible values, we need to plug them into both equations to see which value gives reasonable "B" values.

When A = 2:

B = A - 2 -----> Original equation

B = 2 - 2 -----> Plug in A = 2

B = 0 -----> Subtract

(A - 5)² + (B - 3)² = 18 -----> Original equation

(2 - 5)² + (B - 3)² = 18 ------> Plug in A = 2

(-3)² + (B - 3)² = 18 -----> Subtract within first parentheses

9 + (B - 3)² = 18 -----> Square value within first parentheses

(B - 3)² = 9 -----> Subtract 9 from both sides

B - 3 = 3 -----> Take square root of both sides

B = 6 -----> Add 3 to both sides

When A = 8:

B = A - 2 -----> Original equation

B = 8 - 2 -----> Plug in A = 8

B = 6 -----> Subtract

(A - 5)² + (B - 3)² = 18 -----> Original equation

(8 - 5)² + (B - 3)² = 18 ------> Plug in A = 8

(3)² + (B - 3)² = 18 -----> Subtract within first parentheses

9 + (B - 3)² = 18 -----> Square value within first parentheses

(B - 3)² = 9 -----> Subtract 9 from both sides

B - 3 = 3 -----> Take square root of both sides

B = 6 -----> Add 3 to both sides

As you can see, when A = 2, there are two possible values of "B" depending on the equation. However, when A = 8, both equations give a "B" value of B = 6. Therefore, A = 8 and B = 6 are the answers.

User VinayagaSundar
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