Answer:
Step-by-step explanation:
a) Using the equation of motion
v² = u²+2as
v is the final velocity = 0m/s
u is the initial velocity = 5m/s
S is the distance = 250m
a is the acceleration
Substitute given values:
0² = 5²+2a(250)
-25 = 500a
a = -25/500
a = -0.05m/s²
b) If a = 0.34m/s²
We need to get the initial speed u
v² = u²+2as
0 = u²+2(0.34)(250)
-u² = 170
u² = -170
u = √-170
The square root of a negative number will give a complex number, hence the speed is not possible