Question

A reaction at equilibrium has a standard state Gibbs energy of formation of -1.90 kJ per mole at 298K. Calculate the equilibrium constant.

Answer 1

Kc = 2.15

Step-by-step explanation:

Step 1: Given data

• Standard state Gibbs energy of formation (ΔG°): -1.90 kJ/mol

• Absolute temperature (T): 298 K

• Ideal gas constant (R): 8.314 J/K.mol

• Equilibrium constant (Kc): ?

Step 2: Calculate the equilibrium constant

We will use the following expression.

ΔG° = -R × T × lnKc

-1.90 × 10³ J/mol = -8.314 J/K.mol × 298 K × lnKc

Kc = 2.15