Answer:
Kc = 2.15
Step-by-step explanation:
Step 1: Given data
- Standard state Gibbs energy of formation (ΔG°): -1.90 kJ/mol
- Absolute temperature (T): 298 K
- Ideal gas constant (R): 8.314 J/K.mol
- Equilibrium constant (Kc): ?
Step 2: Calculate the equilibrium constant
We will use the following expression.
ΔG° = -R × T × lnKc
-1.90 × 10³ J/mol = -8.314 J/K.mol × 298 K × lnKc
Kc = 2.15