Answer:
CrCl₃.
Step-by-step explanation:
From the question given above, the following data were obtained:
Mass of chromium (Cr) = 22.60 g.
Mass of metal chloride = 68.83 g.
Empirical formula =.?
Next, we shall determine the mass of chlorine (Cl) in the metal chloride. This can be obtained as follow:
Mass of chromium (Cr) = 22.60 g.
Mass of metal chloride = 68.83 g.
Mass of chlorine (Cl) =.?
Mass of chlorine (Cl) = (Mass of metal chloride) – (Mass of chromium)
Mass of chlorine (Cl) = 68.83 – 22.60
Mass of chlorine (Cl) = 46.23 g
Finally, we shall determine the empirical formula for the metal chloride as follow:
Cr = 22.60 g.
Cl = 46.23 g
Divide by their molar mass
Cr = 22.60 / 52 = 0.435
Cl = 46.23 / 35.5 = 1.302
Divide by the smallest
Cr = 0.435 /0.435 = 1
Cl = 1.302 /0.435 = 3
The empirical formula for the metal chloride is CrCl₃