Question

Solve (2x^2-4y+2y^2)(3x-4)

Answer 1

(2x^2-4y+2y^2)(3x-4)

Explanation:

(2x2−4y+2y2)(3x−4)

=(2x2+−4y+2y2)(3x+−4)

=(2x2)(3x)+(2x2)(−4)+(−4y)(3x)+(−4y)(−4)+(2y2)(3x)+(2y2)(−4)

=6x3−8x2−12xy+16y+6xy2−8y2

=6x3+6xy2−8x2−12xy−8y2+16y