Solve the system by elimination (please show all the steps!) -2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5

asked Dec 1, 2021 230k views

4 votes

Solve the system by elimination (please show all the steps!)

-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

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3 votes

Answer:

i think its z%/67

Explanation:

becuase if you add it up it is 68 but if you sub on it its ether 67 or 63

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